Question

For the reaction shown, compute the theoretical yield of the product in moles for each of the following initial amounts of reactants.

Ti(s)+2Cl2(g)→TiCl4(s)

1. 5 mol Ti; 9 mol C2 2. 12.4 mol Ti; 15.8 mol C2

Answer 1

1)

Balanced chemical equation is:

Ti + 2 Cl2 ---> TiCl4

1 mol of Ti reacts with 2 mol of Cl2

for 5 mol of Ti, 10 mol of Cl2 is required

But we have 9 mol of Cl2

so, Cl2 is limiting reagent

we will use Cl2 in further calculation

According to balanced equation

mol of TiCl4 formed = (1/2)* moles of Cl2

= (1/2)*9

= 4.5 mol

Answer: 4.5 mol

2)

Balanced chemical equation is:

Ti + 2 Cl2 ---> TiCl4

1 mol of Ti reacts with 2 mol of Cl2

for 12.4 mol of Ti, 24.8 mol of Cl2 is required

But we have 15.8 mol of Cl2

so, Cl2 is limiting reagent

we will use Cl2 in further calculation

According to balanced equation

mol of TiCl4 formed = (1/2)* moles of Cl2

= (1/2)*15.8

= 7.9 mol

Answer: 7.9 mol