Question

How many liters of 0.200 M sodium hydroxide do you need to titrate 0.400 L of a 0.100 M diprotic acid to the equivalence point? 0.400 L NaOH

A. 0.200 L NaOH

B. 0.300 L NaOH

C. 0.400 L NaOH

D. 0.500 L NaOH

E. 0.800 L NaOH

Answer #1

Given the volume of the diprotic acid, V = 0.400 L

Concentration of the diprotic acid, M = 0.100 M

Hence moles of the diprotic acid = MxV = 0.100M x 0.400 L = 0.0400 L

Since it is a diprotic acid it will require the base equals to double the moles of the diprotic acid taken.

Hence moles of base(NaOH) required = 2 x 0.0400 L = 0.08 mol

Given the concentration of NaOH, M = 0.200M

Let the volume of NaOH added ve 'V' L

Hence moles of NaOH added = MxV = 0.200xV mol

Now 0.200xV mol = 0.08 mol

=> V = 0.08 / 0.200 = 0.400 L NaOH

Hence (c) is the correct answer

You titrate 25.0 mL of 0.15 M HCl with 0.10 M sodium
hydroxide.
a. What is the pH after 20.0 mL NaOH have been added?
b. How many mL of NaOH are required to reach the equivalence
point?

You titrate 10.0 mL of 0.30 M acetic acid with 0.10 M sodium
hydroxide.
a. What is the pH of the solution after you have added 10.00 mL
of NaOH?
b. What is the pH of the solution at the equivalence
point?

You are titrating 0.200 L of a 0.400M monoprotic weak acid with
a strong base that is 0.800 M.
Ka= 4.8x10^-6
a) At first, there is 0.200 L of 0.400M acid and no strong base.
What is the pH?
b) After 35.0 mL of 0.800 M strong base is added, what is the
pH?
c) How many mL of 0.800 M strong base must be added to reach the
half equivalence point?
d) What is the pH of the equivalence...

A solid sample of zinc hydroxide is added to 0.340 L of 0.400 M
hydrobromic acid. The solution that remains is still acidic. It is
then titrated with 0.400 M sodium hydroxide solution, and it takes
90.5 mL of the sodium hydroxide solution to reach the equivalence
point.
What mass of zinc hydroxide was added to the hydrobromic acid
solution?

Show your work and explain how you would find out how many
liters of 0.500 M H3PO4 it would take to react with 8.00 L of 0.100
M NaOH.

If a sample of sodium hydroxide is titrated with 50.00 mL of
0.400 M nitric acid, how many
grams of the base are in the sample?

How many milliliters of a 1.0 M sodium hydroxide is added to
reach the second half equivalence point in the titration of 25 mL
of a 1.0 M acid titration of H2A?

1. A 100.0-mL sample of 0.500 M sodium hydroxide is titrated
with 0.100 M nitric acid. Calculate the pH before the titration
begins.
2. A 1.0-L buffer solution contains 0.100 mol HCN and 0.100 mol
LiCN. The value of Ka for HCN is 4.9 x 10-10. Because the initial
amounts of acid and conjugate base are equal, the pH of the buffer
is equal to pKa = -log (4.9 x 10-10) = 9.31. Calculate the new pH
after the addition...

The following questions involve the reaction of sodium hydroxide
and succinic acid. Succinic acid is diprotic: the acid
(H2C4H4O4) reacts with
two of its hydrogens to give
C4H4O42-. The balanced
"molecular" equation for the reaction has coefficients of 2 for
NaOH and 1 for succinic acid:
2 NaOH (aq) + H2C4O4 (aq)
--> Na2C4H4O4 (aq) +
2 H2O (l)
A student weights 1.700 g of succinic acid and dissolves it in
water in a 250.0 mL volumetric flask. A 25.00...

Consider the titration of 40.0 mL of 0.250 M HF with 0.200 M
NaOH. How many milliliters of base are required to reach the
equivalence point? Calculate the pH at the following points:
a)After the addition of 10.0 mL of base
b)Halfway to the equivalence point
c)At the equivalence point
d)After the addition of 80.0 mL of base

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 50 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 3 hours ago

asked 3 hours ago

asked 3 hours ago

asked 3 hours ago