Question

How does dried Polypodium sp. react to water?

How does dried Polypodium sp. react to water?

Science   Biology   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

P. polypodioides vacuole contents solidified and remain undamaged up to 97 percent water loss. The photosynthetic activity varies as per water content in the range of 20-100 percent. A dried leaf regains almost 100 percent of its photosynthetic activity upon immersion in water in the first 30 min of rehydration, provided incisions had been made into the leaf before drying. Anaerobic conditions inhibit this revival though cutting of scales can nullify this as well.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
What does it mean to say that HCN has a sp-s overlap, sp-sp overlap and a...
What does it mean to say that HCN has a sp-s overlap, sp-sp overlap and a p-p overlap? My teacher went over this in class and i am completely lost. There is a single bond between H and C, a triple bond between C and N with a lone pair on the far side of N.
Potassium metal and water react to form potassium hydroxide and hydrogen gas. If you react 1.12g...
Potassium metal and water react to form potassium hydroxide and hydrogen gas. If you react 1.12g of potassium metal and 15.0mL of water (density=.99997 g/mL) which reactant is the limiting? how many grams of potassium hydroxide are formed?how many grams of potassium metal remain? how many grams of water remain? (Hint: balenced equation)
Air is dried from a partial pressure of 50 mm Hg of water vapor to a...
Air is dried from a partial pressure of 50 mm Hg of water vapor to a partial pressure of 10 mm Hg. The temperature of the entering air is 524°F and the pressure is constant at 760 mm Hg. How many gallons of liquid water are removed per 1000 ft3 of entering air?
1. Calculate the mass of dried Na2H2EDTA•2H2O needed to prepare exactly 100.00mL of a 0.0100 M...
1. Calculate the mass of dried Na2H2EDTA•2H2O needed to prepare exactly 100.00mL of a 0.0100 M solution. Then, calculate the mass of CoCl2•6H20 required to react completely with 10.0mL of your 0.0100 M EDTAs solution (include 6 molecules of water in molecular weight calculation)
In an orange peel industry, a fresh orange peel containing 80% water and 20% dried orange...
In an orange peel industry, a fresh orange peel containing 80% water and 20% dried orange peel is dried for an hour. The orange peel going out from the dryer has a composition of: 60% orange peel and the rest is water. It is known that in the dryer, there is an evaporation of water with the rate of 100 kg water/hour (% in this problem is in weight %) a) Draw a block diagram for the process, completed with...
Mixtures and Chemical Reactions An Alka-Seltzer antacid tablet reacts vigorously with water. But how does this...
Mixtures and Chemical Reactions An Alka-Seltzer antacid tablet reacts vigorously with water. But how does this tablet react to a solution of half water and half corn syrup? Propose an explanation involving the relationship between reaction speed and the frequency of molecular collisions.
TiCl4 reacts with THF to form Ticl4(thf)2 why does Ticl4(thf)2 react more slowly with water than...
TiCl4 reacts with THF to form Ticl4(thf)2 why does Ticl4(thf)2 react more slowly with water than Ticl4?
The literature value for the K_(sp) of Ca(OH)_2 is 4.68x10^-6. How does the value you determined...
The literature value for the K_(sp) of Ca(OH)_2 is 4.68x10^-6. How does the value you determined in the lab compare with this result? Explain what may have caused your results to differ from value. (Clearly explain what may have happened. Should you have obtain the literature value? Clearly explain how this could have happened?)
A 5250 g piece of wood (sp. gr.=0.50) floats on water. What minimum mass of lead,...
A 5250 g piece of wood (sp. gr.=0.50) floats on water. What minimum mass of lead, hung from the wood by a string, will cause it to sink?
0.499g of dried KHP is dissolved in 35 mL of distilled water and titrated with KOH....
0.499g of dried KHP is dissolved in 35 mL of distilled water and titrated with KOH. If it took 24.40mL of KOH to reach an end point determine the concentration of KOH. I got 0.1 M KOH. But if you forgot to dry the above KHP sample and it was later determined to contain 5.00% water by weight what would be the actual concentration of KOH? This part has me stumped. I would appreciate the help.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT