Question

7. Percent of each of the following amino acids that would account for radioactivity on the filter if the nucleic acid polymer used in a Khorana copolymer experiment was 5’-AGUG-3”

A) 50% Ser, 50% Val

B) 33% Ser, 33% Val, 33% Glu

C) 25% Ser, 25% Val, 25% stop, 25% Glu

D) 25% Ser, 25% His, 25% Thr, 25% Leu

E) 50% His, 25% Thr, 25% Leu

11. Which of the following is most responsible for the C value paradox?

A) Repetitive sequences

B) rRNA genes

C) Protein sequence complexity

D) Introns

E) Regulatory sequences

12. In creating a gene knockout in a mouse, why is the initial candidate mouse a chimera?

A) Only some tissue culture cells receive the DNA that will swap out the wild type gene

B) Only some tissue culture cells with the introduced DNA will have a recombination event

C) Only some of the cells in the blastocyst that develops into an adult mouse will have come from the tissue culture cells

D) The initial candidates are heterozygous for the knockout

E) The gene that is knocked out will be euchromatin in some cells and heterochromatin in others

Answer 1

7) if the copolymer agug used than the sequence would be

AGU GAG UGA GUG......

amino acid repeat will be: Ser-glu-stop-val each at 25%

So, that answer is 'c'.

11) c-value paradox-is a phenomenon which determines how c-value or genetic content of an organism irrelevant to its complexity. The high amount of DNA is organisms mainly atributed to its repetitive sequences in DNA. So, the answer is 'A'.

12) chimeric mice produced via micro injecting the targeted embryonic cells into blastocyst of mice. Hence the knock out genes stick to the tissues developed from injected cells and remaining mice is come from tissue culture cells. Hence initial gene knockout mouse will be a chimaera. So, the answer is 'c'.