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If you performed a five-fold serial dilution, what is the concentration of the third tube? Assume...

If you performed a five-fold serial dilution, what is the concentration of the third tube? Assume the first tube has 2 g/mL concentration.
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Answer #1

five-fold serial dilution was made, so dilution factor at each step=5

dilution factor in the third tube ( third step)= dilution factor in tube 1 dilution factor in tube 2 dilution factor in tube 3=555=125

so the concentration in the third tube= original concentration/dilution factor in the third tube

= 2 g/ mL/125

= 0.016 g/mL

concentration of the third tube = 0.016 g/mL

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