Question

Assume that the genes for tail length and fang length in Towson Tigers are tightly linked....

Assume that the genes for tail length and fang length in Towson Tigers are tightly linked. Further assume that long tails (L) are dominant to short tails (l) and that long fangs (F) are dominant to short fangs (f). Tigers from two true breeding strains, one with long tails and short fangs and the other with short tails and long fangs are crossed to produce an F1 generation, then those cubs are mated to produce an F2 generation

A. What is the genotype of each of the original parents?

B. What is the genotype and phenotype of the cubs in the F1 generation?

C. What gametes can each of the F1 animals produce?

D. What proportion of the F2 animals will have long tails and short fangs?

E. What proportion of the F2 animals will have long tails and long fangs?

When posting the answer, can the answer be mentioned step by step and shortly explained if possible. I am just having a slight problem understanding.

Thank you

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Answer #1

Both genes are completely linked i.e. they do not exhibit independnet assortment = They behave as a single unit
L = Long tails = Dominant
l = Short tails = Recessive
F = Long fangs = Dominant
f = Short fangs = Recessive

Parent 1 = Long tails with short fangs = LLff
Parent 2 = Short tails with long fangs = llFF

Parental cross: LLff X llFF
Gametes produced: (Lf) X (lF)
F1 progeny: Lf/lF
F1 phenotype = Long tails and long fangs

F1 selfing: Lf/lF X Lf/lF
Gametes produced: (Lf) (lF) X (Lf) (lF)
F2 progeny:
Lf/Lf = Long tails with short fangs
Lf/lF = Long tails with long fangs
lF/Lf = Long tails with long fangs
lF/lF = Short tails with long fangs

Frequency of the progeny with long tails and short fangs = 1/4 = 25%
Frequency of the progeny with long tails and long fangs = 1/2 = 50%


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