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Squeaky Squirrels tails and hair color are controlled by genes on different chromosomes. Bushy, long tails...

Squeaky Squirrels tails and hair color are controlled by genes on different chromosomes. Bushy, long tails (T) are dominant to short, thin tails (t) and Black hair (B) is dominant to grey (b) hair. A true breeding black squirrel with bushy, long tail is mated with a grey squirrel with short, thin tail. The F1 generation are then bred with grey squirrels with short, thin tails to produce the F2 generation.

A. What is the GENOTYPE of the parent with grey hair and a short, thin tail?

B. What is the GENOTYPE of the squirrels in the F1 generation?

C. What proportion of the F2 would have black hair and bushy, long tails?   

D. What proportion of the F2 would be have black hair and thin, short tails?

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Answer #1

Answer:

A). Genotype of the parent with grey hair and a short, thin tail = bbtt

B).

Black, bushy long tail (BBTT) x grye, short, thin tail (bbtt)----Parents

BbTt (black, bushy long tail)---------------------------------------F1

Genotype of the squirrels in the F1 generation = BbTt

C).

BbTt x BbTt ---F1 selfcross

Bb x Bb = B_ (3/4) & bb (1/4)

Tt x Tt = T_ (3/4) & tt (1/4)

The proportion of the F2 would have black hair and bushy, long tails = B_T_ = ¾ * ¾ = 9/16

D).

The proportion of the F2 would have black hair and thin, short tails = B_tt = ¾ * ¼ = 3/16

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