Write a formal proof where you define a function to prove that the sets 3Z and 6Z have the same cardinality, meaning |3 Z| = |6 Z|. 3Z = {..., −3, 0, 3, 6, 9, ...} and 6Z = {..., −6, 0, 6, 12, 18, ...}
Z = integers
Consider the function defined by
We will show that this is a bijection and thus it will follow that
Let us assume that
Hence, is injective.
For any , we have
Note that
since
Thus, is surjective.
Hence, is bijective and the result follows.
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