Question

Newton's law of cooling is: du/dt = -k (u-T) where u(t) is
temperature of an object, t is in hours, T is a constant ambient
temperature, and k is a positive constant.

Suppose a building loses heat in accordance with Newton's law of
cooling. Suppose that the rate constant k has the value 0.15 hr^-1
. Assume that the interior temperature is Ti = 77F, when the
heating system fails. If the external temperature is T = 5F, how
long will it take for the interior temperature to fall to T1 =
35F?

Answer #1

Newton's law of cooling/heating states that the time
rate of change of temperature of a cooling/heating object is
proportional to the difference between the temperature of the
object and the ambient temperature of the medium where the object
resides.
If we let Ta represent the ambient temperature and T represent
the temperature of the object then a DE representing this situation
is
dT/dt=k(T−Ta)
where k<0.
When a coil of steel is removed from an annealing furnace its
temperature is 684...

Question B:
Newton's law of cooling states
dθ/dt = −k (θ−T)
where ? is the temperature at time t, T is the constant
surrounding temperature and k is a constant.
If a mass with initial temperature, θ0, of 319.5 K is
placed in a surroundings of 330.5 K, and k is 0.011 s-1
, what is its temperature after 4.7 minutes? Give your answer to 4
significant figures and remember to use units.
____________

(1 point) Newton's Law of Cooling states that the rate of
cooling of an object is proportional to the temperature difference
between the object and its surroundings. Suppose t is time, T is
the temperature of the object, and Ts is the surrounding
temperature. The following differential equation describes Newton's
Law dT/dt=k(T−Ts), where k is a constant. Suppose that we consider
a 95∘C cup of coffee in a 25∘C room. Suppose it is known that the
coffee cools at a...

Newton’s law of cooling states that dx/dt = −k(x − A) where x is
the temperature, t is time, A is the ambient temperature, and k
> 0 is a constant. Suppose that A = A0cos(ωt) for some constants
A0 and ω. That is, the ambient temperature oscillates (for example
night and day temperatures). a) Find the general solution. b) In
the long term, will the initial conditions make much of a
difference? Why or why not?

This exercise uses Newton's Law of Cooling.
Newton's Law of Cooling is used in homicide investigations to
determine the time of death. The normal body temperature is 98.6°F.
Immediately following death, the body begins to cool. It has been
determined experimentally that the constant in Newton's Law of
Cooling is approximately k = 0.1947, assuming time is
measured in hours. Suppose that the temperature of the surroundings
is 55°F.
(a) Find a function T(t) that models the
temperature t hours after...

Newton's Law of Cooling tells us that the rate of change of the
temperature of an object is proportional to the temperature
difference between the object and its surroundings. This can be
modeled by the differential equation dTdt=k(T−A)dTdt=k(T-A), where
TT is the temperature of the object after tt units of time have
passed, AA is the ambient temperature of the object's surroundings,
and kk is a constant of proportionality.
Suppose that a cup of coffee begins at 179179 degrees and,...

dT/dt = k(T − A), where T is the temperature of the object, t is
time, k is the proportionality constant, and A is the constant
ambient temperature. T (t) = A + Ce^kt is the general solution.
Apply the solution to the following scenario: A Police Department
officer discovered a corpse in a downtown alley at 1130pm on a
night where the constant temperature was 40 degrees Fahrenheit. As
she had been trained to do, she immediately recorded the...

Newton's law of cooling states that the temperature of an object
changes at a rate proportional to the different between its
temperature and that of its surroundings. Suppose that the
temperature of a cup of coffee obeys Newton's law of cooling. If
the coffee has a temperature of 200 degrees F when freshly poured,
and 1 min later has cooled to 190 degrees F in a room at 70 degrees
F, determine when the coffee reaches a temperature of 150...

Newton’s Law of Cooling tells us that the time rate of chnge in
temperature T(t) of a body immersed in a medium of constant
temperature A is proportional to the difference A − T.The DE
modeling this is dT dt = k(A − T). A cup of hot chocolate is
initially 170◦ F and is left in a room with an ambient temperature
of 70◦ F. Suppose that at time t = 0 it is cooling at a rate of...

Newton’s law of cooling states that the rate of change of the
temperature T of an object is proportional to the temperature
difference between the temperature S of the surroundings and the
temperature T. dT dt = k(S − T) A cup of tea is prepared from
boiling water at 100 degrees and cools to 60 degrees in 2 minutes.
The temperature in the room is 20 degrees. 1. What will the
temperature be after 15 minutes?

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 42 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 3 hours ago

asked 3 hours ago

asked 3 hours ago

asked 3 hours ago

asked 3 hours ago