Consider a function x2 − 3 = 0 . Then with the starting point x0 = 1 , if we perform three iterations of Newton-Rhapson Method, we have the following:
(Note that your answer format should be x.xxxx. For example, 2 ->, 2.0000 or 1.34 -> 1.3400, or 1.23474 - > 1.2374, or 1.23746->1.2375)
x1 =
x2 =
x3 =
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