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Using tableau method, proof F is a tautology. F: (A → C) → [(B → C)...

Using tableau method, proof F is a tautology.

F: (A → C) → [(B → C) → ((¬A → B) → C)]

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Here I'm using truth value of implication.here T then F is F otherwise all are T.and the last column gives all values are T therefore given F is a tautalogy.answer is below thank you.

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