The revenue function of a company is given by R(x)=-2x^2+25x+150, the cost function is given by C(x)=13x+100
a. Find the marginal cost and marginal revenue function.
b. Find the production level x where the profit is maximized. Then find the maximum profit.
Requirement (a):
Marginal Cost function = Derivative of x for C(x) = 13X + 100 i.e. 13 [MC(x) = 13]
Marginal Revenue Function = Derivative of x for R(x) = -2x^2 + 25x + 150 i.e. -4x + 25 [MR(x) = -4x + 25]
Requirement (b):
Profit is maximum at a level where marginal revenue is equal to marginal cost (MR = MC)
i.e. -4x + 25 = 13
-4x = 13 - 25
-4x = -12
x = 3
The production level at which profit is maximum is 3 units
Revenue : R(x=3) = -[2*(3^2)] + (25 * 3) + 150
R (3) = -18 + 75 + 150
R (3) = 207
Cost : C(x=3) = (13 * 3) + 100
C (3) = 139
Maximum Profit = R (x=3) - C (x=3)
= 207 - 139 i.e. 68
The maximum profit is $68.
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