The total revenue function for a certain product is given by
R=590x dollars, and the total cost function for this product is
C=15,000 +50x + x squared 2 dollars, where x is the number of units of the product that are produced and sold.
a. |
Find the profit function. |
b. |
Find the number of units that gives maximum profit. |
c. |
Find the maximum possible profit. |
The total revenue is R(x) = 590x
& The total cost is, C(x) = 15000 + 50x + x²
So, the profit function is,
P(x) = R(x) - C(x)
= 590x - (15000 + 50x + x²)
= - x² + 540x - 15000
we need to maximize P(x) with respect to x
So, P'(x) = - 2x + 540
&, P"(x) = - 2 < 0
So, for optimum profit, we must have, P'(x) = 0
So, 2x = 540
So, x = 270
So, (b) 270 units are to be sold for maximum profit.
(c) the maximum profit is,
P(270) = 540x270 - 270² - 15000 = 57900
So, maximum possible profit is 57900 dollars
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