If the average number of occurrences for a Poisson process is 2 occurrences per five minute time interval, the probability of getting 2 occurrences over a five minute interval is _______.
a. 0.3233 b. 0.2707 c. 0.6767 d. 0.8038 e. 0.1822
Solution :
Given that ,
mean = = 2
Using poisson probability formula,
P(X = x) = (e- * x ) / x!
P(X 2) = 1 − P( X 2)
P(X 2) = 1 - ( P(X = 0) + P(X = 1) + P(X = 2))
P(X 2) = 1 - ( (e-2 * 20) / 0! + (e-2 * 21) /1! + (e-2 * 22) / 2!)
P(X 2) = 1 - 0.6767
P(X 2) = 0.3233
Probability = 0.3233
Option a is correct.
The answer is 0.3233
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