Question

Consider a Poisson distribution with a mean of two occurrences
per time period.

- Which of the following is the appropriate Poisson probability
function for one time period?

**1****2****3**

SelectEquation #1Equation #2Equation #3 - What is the expected number of occurrences in three time
periods?

- Select the appropriate Poisson probability function to
determine the probability of
*x*occurrences in three time periods.

**1****2****3**

SelectEquation #1Equation #2Equation #3 - Compute the probability of two occurrences in one time period
(to 4 decimals).

- Compute the probability of four occurrences in three time
periods (to 4 decimals).

- Compute the probability of seven occurrences in two time periods (to 4 decimals).

Answer #1

a)

lambda = mean = 2

b)

for 3 periods

expected number = 2 * 3 = 6

c)

for 3 time period

mean = 6

hence

d)

P(X = 2) = e^(-2) *2^2/2! = 0.2707

e)

P(Y = 4) = e^(-6) * 6^4/4! = 0.1339

f)

P(Z = 7) = e^(-4) *4^7/7! = 0.0595

Please give me a thumbs-up if this helps you out. Thank you!
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