The U.S. Dairy Industry wants to estimate the mean yearly milk consumption. A sample of 15 people reveals the mean yearly consumption to be 62 gallons with a standard deviation of 22 gallons. Assume the population distribution is normal. (Use t Distribution Table.)
Solution :
Given that,
t /2,df = 2.624
Margin of error = E = t/2,df * (s /n)
= 2.624 * (22 / 15)
Margin of error = E = 14.905
The 98% confidence interval estimate of the population mean is,
- E < < + E
62 - 14.905 < < 62 + 14.905
47.095 < < 76.905
(47.095 , 76.905)
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