The U.S. Dairy Industry wants to estimate the mean yearly milk consumption. A sample of 12 people reveals the mean yearly consumption to be 56 gallons with a standard deviation of 16 gallons. Assume the population distribution is normal. (Use t Distribution Table.)
a. What is the value of the population mean?
b. What is the best estimate of this value?
c. For a 99% confidence interval, what is the value of t?
Solution :
Given that,
a) - E < < + E
b)
Point estimate = = 56
s = 16
n = 56
c)
Degrees of freedom = df = n - 1 = 56 - 1 = 55
At 99% confidence level the t is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
t /2,df = t0.005,55 = 2.668
value of t = 2.668
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