Question

A sample of 36 children was selected to participate in a task to increase their memory....

A sample of 36 children was selected to participate in a task to increase their memory. After completing the task the children’s memories are measured. The population mean is 15, the sample mean is 16, and the sum of squares is 100. Using a one-tail test with .05 significance, did the task improve children’s memories?

Group of answer choices

Yes, the treatment was statistically significant

No, the treatment was not statistically significant

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A common memory task is the classification of objects into categories. For example, a table is...
A common memory task is the classification of objects into categories. For example, a table is a piece of furniture; a dog is an animal, etc. This classification capability was used in a recent study of divided attention. Elderly adults were randomly selected from those answering a newspaper advertisement, and randomly assigned to two conditions: divided attention and no divided attention. Subjects in the "divided attention" group were told to memorize a list of 36 words while simultaneously listening to...
A random sample is selected from a normal popula-tion with a mean of μ = 40...
A random sample is selected from a normal popula-tion with a mean of μ = 40 and a standard deviation of σ = 10. After a treatment is administered to the individuals in the sample, the sample mean is found to be M = 46. How large a sample is necessary for this sample mean to be statistically significant? Assume a two-tailed test with alpha = .05.
The following data are from a completely randomized design. Treatment Treatment Treatment A B C 32...
The following data are from a completely randomized design. Treatment Treatment Treatment A B C 32 46 33 30 45 36 30 46 35 26 48 36 32 50 40 Sample mean 30 47 36 Sample variance 6 4 6.5 At the  = .05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment Sum of Squares, Error Mean Squares,...
Treatment A Treatment B Treatment C 32 44 34 30 43 37 30 44 36 26...
Treatment A Treatment B Treatment C 32 44 34 30 43 37 30 44 36 26 46 37 32 48 41 Sample mean 30 45 37 Sample variance 6 4 6.5 a. At the X= 0.05 level of significance, can we reject the null hypothesis that the means of the three treatments are equal? Compute the values below (to 1 decimal, if necessary). Sum of Squares, Treatment Sum of Squares, Error Mean Squares, Treatment Mean Squares, Error Calculate the value...
Data: A simple random sample of school children was categorized based on the level of school...
Data: A simple random sample of school children was categorized based on the level of school and the children’s preference for a mother working outside the home. Elementary Middle High Working School School School Mothers Children Children Children Prefer 37 48 89 No Preference 63 52 11 Use the p-value method and a 0.5% significance level to test the claim that the populations of elementary school children, middle school children, and high school children exhibit homogeneous preferences for working mothers....
A random sample is selected from a normal population with a mean of µ = 30...
A random sample is selected from a normal population with a mean of µ = 30 and a standard deviation of σ= 8. After a treatment is administered to the individuals in the sample, the sample mean is found to be x̅ =33. Furthermore, if the sample consists of n = 64 scores, is the sample mean sufficient to conclude that the treatment has a significant effect? Use a two-tailed test with α = .05. 4a. Which of the following...
A random sample of 36 values is drawn from a mound-shaped and symmetric distribution. The sample...
A random sample of 36 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample standard deviation is 2. Use a level of significance of 0.05 to conduct a two-tailed test of the claim that the population mean is 10.5. (a) Is it appropriate to use a Student's t distribution? Explain. Yes, because the x distribution is mound-shaped and symmetric and σ is unknown.No, the x distribution is skewed left.     No, the x distribution...
A random sample of 36 values is drawn from a mound-shaped and symmetric distribution. The sample...
A random sample of 36 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 8 and the sample standard deviation is 2. Use a level of significance of 0.05 to conduct a two-tailed test of the claim that the population mean is 7.5. (a) Is it appropriate to use a Student's t distribution? Explain. Yes, because the x distribution is mound-shaped and symmetric and σ is unknown. No, the x distribution is skewed left.     No, the...
A random sample of 36 values is drawn from a mound-shaped and symmetric distribution. The sample...
A random sample of 36 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 14 and the sample standard deviation is 2. Use a level of significance of 0.05 to conduct a two-tailed test of the claim that the population mean is 13.5. (a) Is it appropriate to use a Student's t distribution? Explain. Yes, because the x distribution is mound-shaped and symmetric and σ is unknown.No, the x distribution is skewed left.    No, the x distribution...
A random sample of 36 values is drawn from a mound-shaped and symmetric distribution. The sample...
A random sample of 36 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 9 and the sample standard deviation is 2. Use a level of significance of 0.05 to conduct a two-tailed test of the claim that the population mean is 8.5. (a) Is it appropriate to use a Student's t distribution? Explain. Yes, because the x distribution is mound-shaped and symmetric and σ is unknown.No, the x distribution is skewed left.    No, the x distribution...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT