Question

If the probability of Nasser hitting the target is 0.9 and the probability of Yusef hitting the target is 0.8, a) What is the probability that at least one of the two will hit the target? B) What is the likelihood of both hitting the target?
(Guidance: Use the Probability Tree)

Answer 1

Solution:

Event A : Nasser hitting the target

Event B :  Yusef hitting the target

P(A) = 0.9

P(B) = 0.8

Two events are independent .

So ,

P(A AND B) = P(A) * P(B) = 0.9 * 0.8 = 0.72

a)

P(at least one of the two will hit the target)

= P(A B)

= P(A) + P(B) - P(A B)

= 0.9 + 0.8 - 0.72

= 0.98

P(at least one of the two will hit the target) = 0.98

b)

P(both hitting the target)

= P(A AND B)

= 0.72

P(both hitting the target) = 0.72