Question

In a survey sample of 100 people, about 28% work less than 40 hours per week....

In a survey sample of 100 people, about 28% work less than 40 hours per week. Calculate a 90% confidence interval for the proportion of persons who work less than 40 hours per week.

Report the lower limit and the upper limit. Round each to the second decimal place.

( _______, ___________ )

Homework Answers

Answer #1

Solution :

Given that,

Point estimate = sample proportion = = 0.28

1 - = 1 - 0.28 = 72

Z/2 = 1.645

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 1.645 * (((0.28 * 0.72) / 100)

Margin of error = E = 0.07

A 90% confidence interval for population proportion p is ,

- E < p < + E

0.28 - 0.07 < p < 0.28 + 0.07

0.21 < p < 0.35

lower limit and upper limit (0.21 , 0.35)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The mean number of hours of part-time work per week for a sample of 278 Metro...
The mean number of hours of part-time work per week for a sample of 278 Metro State students is 20. If the margin of error for the population mean with a 95% confidence interval is 1.5, construct a 95% confidence interval for the mean number of hours of part-time work per week for Metro State University students. (4 points) Lower Limit: ____________ Upper Limit: ____________
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 40 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.1 hours with a standard deviation of 0.97 hours. You want to construct a 99% confidence interval for the mean nightly hours of...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 45 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.1 hours with a standard deviation of 0.86 hours. You want to construct a 99% confidence interval for the mean nightly hours of...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 45 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.1 hours with a standard deviation of 0.97 hours. You want to construct a 99% confidence interval for the mean nightly hours of...
Suppose you perform a study about the hours of sleep that college students get. You know...
Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 35 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.2 hours with a standard deviation of 0.97 hours. You want to construct a 99% confidence interval for the mean nightly hours of sleep for all college...
Some college graduates employed full-time work more than 40 hours per week, and some work fewer...
Some college graduates employed full-time work more than 40 hours per week, and some work fewer than 40 hours per week. We suspect that the mean number of hours worked per week by college graduates, μ , is different from 40 hours and wish to do a statistical test. We select a random sample of college graduates employed full-time and find that the mean of the sample is 42 hours and that the standard deviation is 4 hours. What are...
Suppose you perform a study about the hours of sleep that college students get. You know...
Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 35 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.4 hours with a standard deviation of 0.97 hours. You want to construct a 95% confidence interval for the mean nightly hours of sleep for all college...
A random sample of 994 people was taken. 262 of the people in the sample favored...
A random sample of 994 people was taken. 262 of the people in the sample favored Candidate A. Find 90% confidence interval for the true proportion of people who favors Candidate A. Enter in the lower limit of the confidence interval you found.
A random sample of 803 people was taken. 154 of the people in the sample favored...
A random sample of 803 people was taken. 154 of the people in the sample favored Candidate A. Find 90% confidence interval for the true proportion of people who favors Candidate A. Enter in the lower limit of the confidence interval you found.
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 50 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.2 hours with a standard deviation of 0.97 hours. We want to construct a 95% confidence interval for the mean nightly hours of...