Question

In a pickle ~ There is a beautiful hill station in India called ‘Kurseong’. Besides breathtaking views, this town is also famous for its locally made spicy pickle called Tittira. A random group of tourists from different parts of the world were asked to taste Tittira and 19.61% of tourists said they liked it. The estimated standard error of the sample proportion is 0.0421.

A normal distribution can be used to model the sampling distribution of sample proportion. The pickle salespeople wish to construct a 95% confidence interval for the actual proportion of tourists who like Tittira.

What is the upper bound for the 95% confidence interval? Give your answer to 4 decimal places.

Your Answer:

Answer 1

Solution :

Given that,

Point estimate = sample proportion = = 0.1961

Z = 1.645

Margin of error = E = Z _{/ 2} * (( * (1 - )) / n)

= 1.645 * 0.0421

= 0.0693

Upper bound =   + E = 0.1961 - 0.0693 = 0.1268