Engineers must take into account the width of men's heads when designing motorcycle helmets. The width of men's heads is normally distributed, with a mean of 6.0 inches and a standard deviation of 1.0 inch. Due to economic limitations, helmets will be designed to fit all men, except 2.5% with smaller widths and 2.5% with larger widths. Calculate the minimum and maximum head widths that will fit the helmets.
Solution:
Given that,
mean = = 6.0
standard deviation = = 1.0
Using standard normal table,
a ) P(Z < z) = 2.5%
P(Z < z) = 0.025
P(Z < - 0.61) =0.025
z = -1.96
Using z-score formula,
x = z * +
x = -1.96 * 1.0 +6.0
x = 4.04
The minimum = 4.04
b ) P( Z > z) = 2.5%
P(Z > z) = 0.025
1 - P( Z < z) = 0.025
P(Z < z) = 1 - 0.025
P(Z < z) = 0.975
z = - 0.41
Using z-score formula,
x = z * +
x = 1.96 * 1.0 + 6.0
x = 7.96
The maximum = 7.96
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