Question

Q1

Part A.)

A survey found that women's heights are normally distributed
with mean 63.1 in. and standard deviation 3.5 in. The survey also
found that men's heights are normally distributed with mean 68.6
in. and standard deviation 3.2 in. Consider an executive jet that
seats six with a doorway height of 55.8 in. Complete parts (a)
through (c) below.

a. What percentage of adult men can fit through the door without
bending?

The percentage of men who can fit without bending is

%.

(Round to two decimal places as needed.)

Part B.)

Physicians want to select a minimum temperature for requiring
further medical tests. What should that temperature be, if we want
only 5.0% of healthy people to exceed it? (Such a result is a
false positive, meaning that the test result is positive, but the
subject is not really sick.)

. The minimum temperature for requiring further medical tests
should be degrees Upper F if we want only 5.0% of healthy people
to exceed it.

Answer #1

Part A)

As the data is normally distributed, we can use standard normal z table to estimate the answer

For men

Mean = 68.6

S.d = 3.2

Now height is 55.8

So all the men with height less than 55.8 can enter without bending

So, we need to find p(x<55.8)

Z = (55.8-68.6)/3.2

Z = -4

From z table, p(z<4) = 0.000032

That is 0.000032*100%

= 0.0032%

= 0%

In part 2

Data is missing

You have.not provided the mean and standard deviation

But i can show you the process

From z table, p(z>1.645) = 0.05

So, z = 1.645

And z is given by (x-mean)/s.d

Now you need to determine x here

1.645 = (x-mean)/standard deviation

X is your answer

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