Question

A research team is interested in investigating the effectiveness of a new medication intended to reduce resting heart rate (beats per minute, BPM) in overweight patients. In order to test the medication, the researcher organizes a clinical trial with participants randomly assigned to receive either the new medication or a placebo. Suppose the following table represents the heart rates for a SRS from both groups.

Placebo Group |
Treatment Group |

71 |
67 |

71 |
66 |

68 |
64 |

67 |
64 |

68 |
65 |

69 |
64 |

70 |
59 |

70 |
63 |

69 |
71 |

72 |
64 |

73 |

A) Calculate the standard error for the difference in average heart
rate between the groups.

B) Calculate the pooled standard error for the difference in average heart rate assuming equal variances.

a. SE=1.114 b. SE=1.088 |
||

a. SE=2.441 b. SE=2.119 |
||

a. SE=2.003 b. SE=1.654 |

Answer #1

Placebo | treatment | ||

x_{1} = |
69.82 |
x_{2} = |
64.70 |

s_{1} = |
1.83 |
s_{2} = |
3.06 |

n_{1} = |
11 |
n_{2} = |
10 |

A)

standard error
se=√(S^{2}_{1}/n_{1}+S^{2}_{2}/n_{2})= |
1.114 |

B)

Pooled Variance
Sp^{2}=((n_{1}-1)s^{2}_{1}+(n_{2}-1)*s^{2}_{2})/(n_{1}+n_{2}-2)= |
6.1967 |

standard error se =S_{p}*√(1/n1+1/n2)= |
1.088 |

**correct option is:**

**a. SE=1.114**

**b. SE=1.088**

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none of these
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