Question

A random sample of n = 700 observations from a binomial population produced x = 475...

A random sample of n = 700 observations from a binomial population produced x = 475 successes.

Give the best point estimate for the binomial proportion p. (Round your answer to three decimal places.)

p̂ =

Calculate the 95% margin of error. (Round your answer to three decimal places.)

±

Homework Answers

Answer #1

Solution :

Given that,

n = 700

x = 475

= x / n = 475 / 700 = 0.679

Point estimate = 0.679

1 - = 1 - 0.679 = 0.321

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 1.96 * (((0.679 * 0.321) / 700)

= 0.035

Margin of error is 0.035

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A random sample of n = 1,400 observations from a binomial population produced x = 541...
A random sample of n = 1,400 observations from a binomial population produced x = 541 successes. You wish to show that p differs from 0.4. Calculate the appropriate test statistic. (Round your answer to two decimal places.) z = ?? Calculate the p-value. (Round your answer to four decimal places.) p-value = ??
A random sample of n = 300 observations from a binomial population produced x = 223...
A random sample of n = 300 observations from a binomial population produced x = 223 successes. Find a 90% confidence interval for p. (Round your answers to three decimal places.) to Interpret the interval. In repeated sampling, 10% of all intervals constructed in this manner will enclose the population proportion.There is a 90% chance that an individual sample proportion will fall within the interval.    In repeated sampling, 90% of all intervals constructed in this manner will enclose the population proportion.There...
A random sample of n = 1,500 observations from a binomial population produced x = 413....
A random sample of n = 1,500 observations from a binomial population produced x = 413. If your research hypothesis is that p differs from 0.3, calculate the test statistic and its p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.)
Independent random samples of n1 = 900 and n2 = 900 observations were selected from binomial...
Independent random samples of n1 = 900 and n2 = 900 observations were selected from binomial populations 1 and 2, and x1 = 120 and x2 = 150 successes were observed. (a) What is the best point estimator for the difference (p1 − p2) in the two binomial proportions? p̂1 − p̂2 n1 − n2     p1 − p2 x1 − x2 (b) Calculate the approximate standard error for the statistic used in part (a). (Round your answer to three decimal...
A random sample of size n = 50 is selected from a binomial distribution with population...
A random sample of size n = 50 is selected from a binomial distribution with population proportion p = 0.8. Describe the approximate shape of the sampling distribution of p̂. Calculate the mean and standard deviation (or standard error) of the sampling distribution of p̂. (Round your standard deviation to four decimal places.) mean = standard deviation = Find the probability that the sample proportion p̂ is less than 0.9. (Round your answer to four decimal places.)
A random sample of n = 1,000 observations from a binomial population contained 337 successes. You...
A random sample of n = 1,000 observations from a binomial population contained 337 successes. You wish to show that p < 0.35. Calculate the appropriate test statistic. (Round your answer to two decimal places.) z =   Provide an α = 0.05 rejection region. (Round your answer to two decimal places. If the test is one-tailed, enter NONE for the unused region.) z > z <
A random sample of size n = 40 is selected from a binomial distribution with population...
A random sample of size n = 40 is selected from a binomial distribution with population proportion p = 0.25. (a) What will be the approximate shape of the sampling distribution of p̂? approximately normal skewed symmetric Correct: Your answer is correct. (b) What will be the mean and standard deviation (or standard error) of the sampling distribution of p̂? (Round your answers to four decimal places.) mean 0.25 Correct: Your answer is correct. standard deviation 0.0685 Correct: Your answer...
Chapter 6, Section 1-CI, Exercise 011 Use the normal distribution to find a confidence interval for...
Chapter 6, Section 1-CI, Exercise 011 Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 95% confidence interval for p given that p^=0.34 and n=475. Round your answer for the best point estimate to two decimal places, and your answers for the margin of error and the...
Independent random samples of n1 = 700 and n2 = 590 observations were selected from binomial...
Independent random samples of n1 = 700 and n2 = 590 observations were selected from binomial populations 1 and 2, and x1 = 337 and x2 = 375 successes were observed. (a) Find a 90% confidence interval for the difference (p1 − p2) in the two population proportions. (Round your answers to three decimal places.)
Suppose we have a binomial distribution with n trials and probability of success p. The random...
Suppose we have a binomial distribution with n trials and probability of success p. The random variable r is the number of successes in the n trials, and the random variable representing the proportion of successes is p̂ = r/n. (a) n = 44; p = 0.53; Compute P(0.30 ≤ p̂ ≤ 0.45). (Round your answer to four decimal places.) (b) n = 36; p = 0.29; Compute the probability that p̂ will exceed 0.35. (Round your answer to four...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT