Question

Construct the confidence interval for the population variance for the given values. Round your answers to one decimal place.

n= 27 s^2 = 6.2 , and c = 0.98

What is the lower end point and higher end point ?

Answer 1

Solution :

Given that,

Point estimate = s² = 6.2

²_L = ²_/2,df = 45.642

²_R = ²_{1 - /2,df} = 12.198

The 98% confidence interval for ² is,

(n - 1)s² / ²_/2 < ² < (n - 1)s² / ²_{1 - /2}

26 * 6.2 / 45.642 < ² < 26 * 6.2 / 12.198

3.5319 < ² < 13.2151

Lower endpoint = 3.5319

Higher end point = 13.2151