Question

Construct the confidence interval for the population variance for the given values. Round your answers to one decimal place.

n= 27 s^2 = 6.2 , and c = 0.98

What is the lower end point and higher end point ?

Answer #1

Solution :

Given that,

Point estimate = s^{2} = 6.2

^{2}_{L}
=
^{2}_{/2,df}
= 45.642

^{2}_{R}
=
^{2}_{1 -} _{
/2,df} = 12.198

The 98% confidence interval for
^{2} is,

(n - 1)s^{2} /
^{2}_{/2}
<
^{2} < (n - 1)s^{2} /
^{2}_{1 -} _{
/2}

26 * 6.2 / 45.642 <
^{2} < 26 * 6.2 / 12.198

3.5319 <
^{2} < 13.2151

Lower endpoint = 3.5319

Higher end point = 13.2151

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for the given values. Round your answers to one decimal place.
n=5, s2=21.2, and c=0.98

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deviation for the given values. Round your answers to one decimal
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n=3 , s=7.1 , and c=0.98

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deviation for the given values. Round your answers to one decimal
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n=20n=20, s=4.3s=4.3, and c=0.99

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n=14 and α=0.01.

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