Construct the confidence interval for the population variance for the given values. Round your answers to one decimal place.
n= 27 s^2 = 6.2 , and c = 0.98
What is the lower end point and higher end point ?
Solution :
Given that,
Point estimate = s2 = 6.2
2L
=
2
/2,df
= 45.642
2R
=
21 -
/2,df = 12.198
The 98% confidence interval for
2 is,
(n - 1)s2 /
2
/2
<
2 < (n - 1)s2 /
21 -
/2
26 * 6.2 / 45.642 <
2 < 26 * 6.2 / 12.198
3.5319 <
2 < 13.2151
Lower endpoint = 3.5319
Higher end point = 13.2151
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