Question

Construct the confidence interval for the population variance for the given values. Round your answers to one decimal place.

n=5, s2=21.2, and c=0.98

Answer 1

Solution :

Given that,

Point estimate = s² = 21.2

²_L = ²_/2,df = 13.277

²_R = ²_{1 - /2,df} = 0.297

The 98% confidence interval for ² is,

(n - 1)s² / ²_/2 < ² < (n - 1)s² / ²_{1 - /2}

4 * 21.2 / 13.277 < ² < 4 * 21.2 / 0.297

6.4 < ² < 285.4

(6.4 , 285.4)