Question

Suppose two-distinct integers are chosen from between 5 and 17 inclusive. What is the probability that their product is odd?

Answer 1

The numbers between 5 and 17 are 6 to 16.

Total 11 numbers and pairs are 2 in number.

Total number of pairs =¹¹c₂ = 55

Some important factors. ...

(1) Whenever an even number is multipled by other even number their product is also even.

(2) whenever an even number is multipled by odd number then also the product results to be even.

(3) whenever an odd number is multipled by other odd number their product is also odd.

So, we have to find the probability of odd products.

So, their are total 5 odd numbers between 5 and 17.

So, number of odd pairs = ⁵c₂ = 10

Now, probability that when two distinct numbers chosen will have odd product = 10/55 = 0.18 or 2/11