You wish to test the following claim (HaHa) at a significance
level of α=0.01
Ho:p=0.89
Ha:p<0.89
You obtain a sample of size n=526 in which there are 461 successful
observations.
Determine the test statistic formula for this test.
What is the test statistic for this sample? (Report answer accurate
to three decimal places.)
test statistic =
What is the p-value for this sample? (Report answer accurate to
four decimal places.)
p-value =
The p-value is...
This test statistic leads to a decision to...
As such, the final conclusion is that...
Solution :
This is the left tailed test .
The null and alternative hypothesis is
H0 : p = 0.89
Ha : p < 0.89
n = 526
= x / n = 461 / 526 = 0.88
P0 = 0.89
1 - P0 = 1 - 0.89 = 0.11
Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
= 0.88 -0.89 / [0.89*0.11 / 526]
= −0.995
Test statistic = z = −0.99
P-value = 0.1599
= 0.01
P-value <
0.1599 ≥ 0.01
fail to reject the null
There is not sufficient evidence to warrant rejection of the claim that the population proportion is less than 0.89.
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