Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and the time a patrol car radios that it has arrived at the scene. Over a long period of time, it has been determined that the police response time has a normal distribution with a mean of 7.6 minutes and a standard deviation of 2.3 minutes. For a randomly received emergency call, find the following probabilities. (Round your answers to four decimal places.)
(a) the response time is between 3 and 9 minutes
(b) the response time is less than 3 minutes
(c) the response time is more than 9 minutes
Solution :
Given that ,
mean = = 7.6
standard deviation = = 2.3
a) P(3 < x < 9) = P[(3 - 7.6)/ 2.3) < (x - ) / < (9 - 7.6) / 2.3) ]
= P(-2.00 < z < 0.61)
= P(z < 0.61) - P(z < -2.00)
Using z table,
= 0.7291 - 0.0228
= 0.7063
b) P(x < 3) = P[(x - ) / < (3 - 7.6) /2.3 ]
= P(z < -2.00)
Using z table,
= 0.0228
c) P(x > 9) = 1 - p( x< 9)
=1- p P[(x - ) / < (9 - 7.6) /2.3 ]
=1- P(z < 0.61)
Using z table,
= 1 - 0.7291
= 0.2709
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