If 15% of adults in a certain country work from home, what is the probability that fewer than 48 out of a random sample of 400 adults will work from home? (Round your answer to 3 decimal places)
Solution:
Given that,
P = 0.15
1 - P = 0.85
n = 400
Here, BIN ( n , P ) that is , BIN (400 , 0.15)
then,
n*p = 60 > 5
n(1- P) = 340 > 5
According to normal approximation binomial,
X Normal
Mean = = n*P = 60
Standard deviation = =n*p*(1-p) = 51
We using continuity correction factor
P(X < a ) = P(X < a - 0.5)
P(x < 47.5) = P((x - ) / < (47.5 - 60) / 51)
= P(z < -1.75)
Probability = 0.040
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