Question

ndustry standards suggest that 14 percent of new vehicles
require warranty service within the first year. Jones Nissan in
Sumter, South Carolina, sold 10 Nissans yesterday. **(Round
your mean answer to 2 decimal places and the other answers to 4
decimal places.)**

Compute the mean and standard deviation of this probability distribution. |

Determine the probability that exactly two of these vehicles require warranty service. |

What is the probability exactly one of these vehicles requires warranty service? |

What is the probability that none of these vehicles requires warranty service? |

Answer #1

Solution:

problem on binomal distribution

Here n=10

p=0.14

q=1-p=1-0.14=0.86

mean=np=10*0.14=1.4

standard deviation=sqrt(npq)=sqrt(10*0.14*0.86)=1.0973

MEAN=1.4

STD.DEVIATION=1.0973

Solution-b

Determine the probability that exactly two of these vehicles require warranty service.

P(X=2)

=10c2*0.14^2*0.86^10-2

= 0.2639102

0.2639

Solution-c

What is the probability exactly one of these vehicles requires warranty service?

P(X=1)

=10c1*0.14^1*0.86^10-1

=0.3602584

0.3603

Solution-d:

What is the probability that none of these vehicles requires warranty service?

P(X=0)

=10c0*0.14^0*0.86^10-0

=0.2213

ANSWER;

0.2213

Industry standards suggest that 11 percent of new vehicles
require warranty service within the first year. Jones Nissan in
Sumter, South Carolina, sold 11 Nissans yesterday. (Round your Mean
answer to 2 decimal places and the other answers to 4 decimal
places.)
(a) What is the probability that none of these vehicles requires
warranty service?
Probability=
(b) What is the probability exactly one of these vehicles
requires warranty service?
Probability =
(c) Determine the probability that exactly two of these...

Industry standards suggest that 14% of new vehicles require
warranty service within the first year. Jones Nissan, sold 8
Nissans yesterday. (Round the Mean answer to 2 decimal
places and the other answers to 4 decimal places.)
a. What is the probability that none of these
vehicles requires warranty service?
Probability
b. What is the probability that exactly one of
these vehicles requires warranty service?
Probability
c. Determine the probability that exactly two
of these vehicles require warranty service.
Probability ...

Industry standards suggest that 18% of new vehicles require
warranty service within the first year. Jones Nissan, sold 10
Nissans yesterday. (Round the Mean answer to 2 decimal
places and the other answers to 4 decimal places.)
a. What is the probability that none of these
vehicles requires warranty service?
Probability
b. What is the probability that exactly one of
these vehicles requires warranty service?
Probability
c. Determine the probability that exactly two
of these vehicles require warranty service.
Probability ...

industry standards
suggest that 10% of new vehicles require warranty service within
the first year. Jones Nissan, sold 9 Nissans yesterday.
(Round the Mean answer to 2 decimal places and the other
answers to 4 decimal places.)
a.
What is the probability that none of these vehicles requires
warranty service?
Probability
b.
What is the probability that exactly one of these vehicles requires
warranty service?
Probability
c.
Determine the probability that exactly two of these vehicles
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Probability ...

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places and the other answers to 4 decimal places.)
a. What is the probability that none of these
vehicles requires warranty service?
Probability
b. What is the probability that exactly one of
these vehicles requires warranty service?
Probability
c. Determine the probability that exactly two
of these vehicles require warranty service.
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Suppose 10% of new scooters will require a warranty service
within the first month of its sale. A scooter
manufacturing company sells 1000 scooters in a month. Find the
mean and standard deviation of scooters that
require warranty service.

The average time for a particular LED TV needs ﬁrst service is
415 days with standard deviation of 30 days. The manufacturer gives
one year (365 days) onsite service warranty for newly bought TVs.
Assume that the times for ﬁrst service call are approximately
normally distributed. Let X denote the time until the ﬁrst service
for an LED TV.
a. The distribution of X is (i) Standard normal with mean 0 and
variance 1. (ii) Normal with mean 415 days...

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