Question

Since an instant replay system for tennis was introduced at a major​ tournament, men challenged 14021402 referee​ calls, with the result that 411411 of the calls were overturned. Women challenged 746746 referee​ calls, and 218218 of the calls were overturned. Use a 0.050.05 significance level to test the claim that men and women have equal success in challenging calls. Complete parts​ (a) through​ (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of male tennis players who challenged referee calls and the second sample to be the sample of female tennis players who challenged referee calls. What are the null and alternative hypotheses for the hypothesis​ test? A. Upper H 0H0​: p 1p1equals=p 2p2 Upper H 1H1​: p 1p1not equals≠p 2p2 B. Upper H 0H0​: p 1p1equals=p 2p2 Upper H 1H1​: p 1p1less than

p 2p2 E. Upper H 0H0​: p 1p1not equals≠p 2p2 Upper H 1H1​: p 1p1equals=p 2p2 F. Upper H 0H0​: p 1p1less than or equals≤p 2p2 Upper H 1H1​: p 1p1not equals≠p 2p2 Identify the test statistic. zequals=nothing ​(Round to two decimal places as​ needed.) Identify the​ P-value. ​P-valueequals=nothing ​(Round to three decimal places as​ needed.) What is the conclusion based on the hypothesis​ test? The​ P-value is ▼ less than greater than the significance level of alphaαequals=0.050.05​, so ▼ fail to reject reject the null hypothesis. There ▼ is sufficient is not sufficient evidence to warrant rejection of the claim that women and men have equal success in challenging calls. b. Test the claim by constructing an appropriate confidence interval. The 9595​% confidence interval is nothingless than

Answer 1

(A)Claim:- men and women have equal success in challenging calls

So, it is a two sided hypothesis test

using TI 84 calculator

press stat then tests then 2-PropZTest

enter the data

x1 = 411

n1 = 1402

x2 = 218

n2 = 746

p1 not equal to p2

press enter, we get

test statistic = 0.04

p value = 0.968

Conclusion:- The​ P-value is greater than the significance level of alphaαequals=0.05, so fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that women and men have equal success in challenging calls

(B)

using TI 84 calculator

press stat then tests then 2-PropZInt

enter the data

x1 = 411

n1 = 1402

x2 = 218

n2 = 746

c-level = 0.95

press calculate, we get

(-0.0395, 0.0413)