Question

A horse race has 10 10 entries and one person owns 5 5 of those horses. Assuming that there are no ties, what is the probability that those five five horses finish first comma second comma third comma fourth comma and fifth first, second, third, fourth, and fifth (regardless of order)?

Answer #1

his makes it a combination type problem rather than a
permutation type problem because order doesn't matter.

we have 5 spots.

the probability that one of those 5 horses will be first is
5/10.

the probability that one of the remaining 4 horses will be second
is 4/9.

the probability that one of the remaining 3 horses will be third is
3/8.

the probability that the remaining 2 horses will be fourth is
2/7.

the probability that the remaining horse will be fifth is
1/6.

the total probability is

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