Scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 16. Use the empirical rule to determine the following. (a) What percentage of people has an IQ score between 84 and 116? (b) What percentage of people has an IQ score less than 52 or greater than 148? (c) What percentage of people has an IQ score greater than 116?
a)
for normal distribution z score =(X-μ)/σx | |
here mean= μ= | 100 |
std deviation =σ= | 16.000 |
percentage of people has an IQ score between 84 and 116:
probability = | P(84<X<116) | = | P(-1<Z<1)=68.0% |
b)
percentage of people has an IQ score less than 52 or greater than 148:
P(X<52)+P(X>148)=100-P(52<X<148)=100-P(-3<Z<3)=100-99.7 =0.3%
c)
percentage of people has an IQ score greater than 116:
=P(X>116)=P(Z>1)=16.0%
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