Two random samples are taken, one from among first-year students and the other from among fourth-year students at a public university. Both samples are asked if they favor modifying the student Honor Code. A summary of the sample sizes and number of each group answering yes'' are given below:
First-Years (Pop. 1):Fourth-Years (Pop. 2):n1=93,n2=97,x1=62x2=56First-Years (Pop. 1):n1=93,x1=62Fourth-Years (Pop. 2):n2=97,x2=56
Is there evidence, at an ?=0.07?=0.07 level of significance, to conclude that there is a difference in proportions between first-years and fourth-years? Carry out an appropriate hypothesis test, filling in the information requested.
A. The value of the standardized test statistic:
Note: For the next part, your answer should use interval notation. An answer of the form (??,a)(??,a) is expressed (-infty, a), an answer of the form (b,?)(b,?) is expressed (b, infty), and an answer of the form (??,a)?(b,?)(??,a)?(b,?) is expressed (-infty, a)U(b, infty).
B. The rejection region for the standardized test statistic:
C. The p-value is:
n1=93
n2=97
here z test for comparing proportion will be used
claim
significance level alpha=0.07 , critical values are -1.8119 and +1.8119
pooled sample proportion is
p= 0.621052
standard error of the test:
SE= 0.070404936
So test statistics will be
z= 1.26904
since this is lower tail test
p value= p(z>1.2690)=0.102212
p-value for two tail =2*0.1022=0.2044
Decision making,
p-value >alpha
0.2044>0.07 ……fail to Reject null hypothesis
We don’t have enough evidence to support the claim that p1 is different from p2.
.................
A) Z test statistics =1.2690
B) (-infty,-1.8119 )U(1.8119, infty).
c) p-value=0.2044
.........................
if you have any doubt ask in comment give thumbs up if you like work
Get Answers For Free
Most questions answered within 1 hours.