STATISTICS/PROBABILITY: Let X= the # of heads when 4 coins are tossed.
a.) Find the expected number of heads
b.) Find the variance and standard deviation
so far I have
x | 0 | 1 | 2 | 3 | 4 |
P(x) | 1/16 | 4/16 | 6/16 | 4/16 | 1/16 |
Solution:
The formula for expected number and variance and standard deviation are given as below:
Expected number = mean = ∑XP(X)
Variance = ∑ P(X)*(X - mean)^2
Standard deviation = Sqrt(Variance)
The calculation table is given as below:
X |
P(X) |
XP(X) |
P(X)*(X - mean)^2 |
0 |
0.0625 |
0 |
0.25 |
1 |
0.25 |
0.25 |
0.25 |
2 |
0.375 |
0.75 |
0 |
3 |
0.25 |
0.75 |
0.25 |
4 |
0.0625 |
0.25 |
0.25 |
Total |
1 |
2 |
1 |
Expected number = mean = ∑XP(X) = 2
Expected number = 2
Variance = ∑ P(X)*(X - mean)^2 = 1
Variance = 1
Standard deviation = Sqrt(Variance) = sqrt(1) = 1
Standard deviation = 1
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