Hoping to lure more shoppers downtown, a city builds a new public parking garage | ||||||||
in the central business district. The city plans to pay for the structure through parking | ||||||||
fees. For a random sample of 38 weekdays, daily fees collected averaged $134, | ||||||||
with a standard deviation of $10. | ||||||||
Construct a 90% confidence interval estimate for the mean daily income this parking | ||||||||
garage will generate. Round your final answers to whole numbers. Show your work! | ||||||||
Formula(s), substitutions, answer! Round your z or t value to 3 decimal places. |
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The consultant who advised the city on this project predicted that parking revenues | ||||||||
would average at least $135 per day. Based on your confidence interval, revenues | ||||||||
(could / could not) average at least $135 per day. Briefly defend your answer. | ||||||||
a)
sample mean, xbar = 134
sample standard deviation, s = 10
sample size, n = 38
degrees of freedom, df = n - 1 = 37
Given CI level is 90%, hence α = 1 - 0.9 = 0.1
α/2 = 0.1/2 = 0.05, tc = t(α/2, df) = 1.687
ME = tc * s/sqrt(n)
ME = 1.687 * 10/sqrt(38)
ME = 2.7
CI = (xbar - tc * s/sqrt(n) , xbar + tc * s/sqrt(n))
CI = (134 - 1.687 * 10/sqrt(38) , 134 + 1.687 * 10/sqrt(38))
CI = (131 , 137)
Based on your confidence interval, revenues
( could not) average at least $135 per day.
Because confidence interval contains 135
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