A college prep school advertises that their students are more prepared to succeed in college than other schools. To verify this, they categorize GPA’s into 4 groups and look up the proportion of students at a state college in each category. They find that 7% have a 0-0.99, 21% have a 1-1.99, 37% have a 2-2.99, and 35% have a 3-4.00 in GPA. They then take a random sample of 200 of their graduates at the state college and find that 19 has a 0-0.99, 28 have a 1-1.99, 82 have a 2-2.99, and 71 have a 3-4.00. Can they conclude that the grades of their graduates are distributed differently than the general population at the school? Test at the 0.05 level of significance. A. yes because the p-value is .0620 B. no because the p-value is .0620 C. yes because the p-value is .9379 D. no because the p-value is .9379
Category | Observed Frequency (O) | Proportion, p | Expected Frequency (E) | (O-E)²/E |
0-0.99 | 19 | 0.07 | 200 * 0.07 = 14 | (19 - 14)²/14 = 1.7857 |
1-1.99 | 28 | 0.21 | 200 * 0.21 = 42 | (28 - 42)²/42 = 4.6667 |
2-2.99 | 82 | 0.37 | 200 * 0.37 = 74 | (82 - 74)²/74 = 0.8649 |
3-4 | 71 | 0.35 | 200 * 0.35 = 70 | (71 - 70)²/70 = 0.0143 |
Total | 200 | 1.00 | 200 | 7.3315 |
Test statistic:
χ² = ∑ ((O-E)²/E) = 7.3315
df = n-1 = 3
p-value = CHISQ.DIST.RT(7.3315, 3) = 0.0620
answer: B. no because the p-value is .0620
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