Question

Assume that a sample is used to estimate a population proportion
*p*. Find the 99.5% confidence interval for a sample of size
99 with 26.3% successes. Enter your answer as an
**open-interval** (*i.e.*, parentheses) using
decimals (not percents) accurate to three decimal places.

99.5% C.I. =

Answer should be obtained without any preliminary rounding.
However, the critical value may be rounded to 3 decimal places.

Answer #1

We have given,

n=99

Estimate for sample proportion

Level of significance is =0.005

Z critical value(using Z table)=2.807

Confidence interval formula is

=(0.139,0.387)

99.5% C.I. = (0.139,0.387) |

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