Assume that a sample is used to estimate a population proportion
p. Find the 99.5% confidence interval for a sample of size
99 with 26.3% successes. Enter your answer as an
open-interval (i.e., parentheses) using
decimals (not percents) accurate to three decimal places.
99.5% C.I. =
Answer should be obtained without any preliminary rounding.
However, the critical value may be rounded to 3 decimal places.
We have given,
n=99
Estimate for sample proportion
Level of significance is =0.005
Z critical value(using Z table)=2.807
Confidence interval formula is
=(0.139,0.387)
99.5% C.I. = (0.139,0.387) |
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