Assume that a sample is used to estimate a population proportion
p. Find the 90% confidence interval for a sample of size 247 with
146 successes. Enter your answer as an open-interval (i.e.,
parentheses) using decimals (not percents) accurate to three
decimal places.
90% C.I. =
Answer should be obtained without any preliminary rounding.
However, the critical value may be rounded to 3 decimal places.
Solution :
Given that,
Point estimate = sample proportion = = x / n = 146 / 247 = 0.591
1 - = 1 - 0.591 = 0.409
Z/2 = 1.645
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.645 * (((0.591 * 0.409) / 247)
= 0.051
A 90% confidence interval for population proportion p is ,
- E < p < + E
0.591 - 0.051 < p < 0.591 + 0.051
0.540 < p < 0.642
90% C.I. = 0.540 , 0.642
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