Provide an appropriate response.Find Y such that 56.75% of adults have IQ score greater than Y.
129.6
97.5
102.6
110.7
To solve this problem, let us assume the IQ of adults is normally distributed with a mean of 100 and a standard deviation of 15.
Now, let X denote the IQ score of a randomly selected adult.
Thus, P(X > Y) = 56.75% = 0.5675
Corresponding to X = Y, the Z score is (Y - 100)/15
Thus, P{Z > (Y - 100)/15} = 0.5675
From Z table, the above probability of 0.5675 is satisfied for Z > (-0.17)
Thus, (Y - 100)/15 = -0.17
-> Y = 97.5
Thus, the most appropriate response is 97.5
Get Answers For Free
Most questions answered within 1 hours.