Question

Chicken Delight claims that 92% of its orders are delivered within 10 minutes of the time the order is placed. A sample of 80 orders revealed that 70 were delivered within the promised time. At the 0.01 significance level, can we conclude that less than 92% of the orders are delivered in less than 10 minutes?

A.) What is the decision rule? **(Negative amount should
be indicated by a minus sign. Round your answer to 2 decimal
places.)**

B.) Compute the value of the test statistic. **(Negative
amount should be indicated by a minus sign. Round the intermediate
values and final answer to 2 decimal places.)**

Answer #1

Solution:

Let be the sample proportion.

= x/n = 70/80 = 0.875

Let p be the population proportion.

Null and alternative hypothesis are

H0 : p = 0.92

H1 : p < 0.92

A)

Left tailed test

Critical value is = = -2.33

**Decision Rule : Reject H _{0} if z <
-2.33**

B)

The test statistic z is

z =

= (0.875 - 0.92)/[0.92*(1 - 0.92)/80]

= **-1.48**

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a. What is your decision regarding the below
hypothesis? (Round the final answer to 2 decimal
places.)
H0 is rejected if z
< ...

Chicken Delight claims that 90% of its orders are delivered
within 10 minutes of the time the
order is placed. A sample of 100 orders revealed that 92 were
delivered within the promised
time. At the .10 significance level, can we conclude that more than
90% of the orders are
delivered in less than 10 minutes?

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