Question

Total plasma volume is important in determining the required plasma component in blood replacement therapy for a person undergoing surgery. Plasma volume is influenced by the overall health and physical activity of an individual. Suppose that a random sample of 42 male firefighters are tested and that they have a plasma volume sample mean of x = 37.5 ml/kg (milliliters plasma per kilogram body weight). Assume that σ = 7.60 ml/kg for the distribution of blood plasma.

(a) Find a 99% confidence interval for the population mean blood plasma volume in male firefighters. What is the margin of error? (Round your answers to two decimal places.)

lower limit
upper limit
margin of error

(b) What conditions are necessary for your calculations? (Select all that apply.)

n is large

σ is known

the distribution of weights is uniform

the distribution of weights is normal

σ is unknown

(c) Interpret your results in the context of this problem.

99% of the intervals created using this method will contain the true average blood plasma volume in male firefighters.

1% of the intervals created using this method will contain the true average blood plasma volume in male firefighters.    

The probability that this interval contains the true average blood plasma volume in male firefighters is 0.99.

The probability that this interval contains the true average blood plasma volume in male firefighters is 0.01.

(d) Find the sample size necessary for a 99% confidence level with maximal margin of error E = 2.70 for the mean plasma volume in male firefighters. (Round up to the nearest whole number.)
male firefighters

Answer 1

sample mean of x = 37.5 ml/kg

σ = 7.60 ml/kg for the distribution of blood plasma

n = 42

standard error of sample mean = 7.60/sqrt(42) = 1.173

(a) 99% confidence interval for the population mean blood plasma volume in male firefighters.

Margin of error = Critical test statistc * standard error of sample mean

Critical test statistc for 99% confidence interval = 2.576

Margin or errro = 2.575 * 1.173 = 3.02

Lower limit = 37.5 - 3.02 = 34.48 ml/kg

Upper Limit = 37.50 + 3.02 = 40.52 ml/kg

(b) Here the conditions that are necessary are

σ is known

the distribution of weights is normal

(c) 99% of the intervals created using this method will contain the true average blood plasma volume in male firefighters. Option 1 is correct.

(d) Here Maximal margin of error = 2.70 = 2.576 * 7.60/sqrt(n)

sqrt(n) = (2.576 * 7.60)/2.70 = 7.251

n = 52.57 or 53

so here we will use 53 male firefighters.