A new car that is a gas- and electric-powered hybrid has recently hit the market. The distance travelled on 1 gallon of fuel is normally distributed with a mean of 50 miles and a standard deviation of 7 miles. Find the probability of the following events:
A. The car travels more than 53 miles per gallon.
Probability =
B. The car travels less than 47 miles per gallon.
Probability =
C. The car travels between 42 and 58 miles per gallon.
Probability =
Solution :
Given that ,
A.
P(x >53 ) = 1 - P(x < 53)
= 1 - P[(x - ) / < (53 - 50) / 7)
= 1 - P(z < 0.4286)
= 1 - 0.6659
= 0.3341
Probability = 0.3341
B.
P(x < 47) = P[(x - ) / < (47 - 50) / 7]
= P(z < -0.4286)
= 0.3341
Probability = 0.3341
C.
P(42 < x < 58) = P[(42 - 50)/ 7) < (x - ) / < (58 - 50) / 7) ]
= P(-1.1429 < z < 1.1429)
= P(z < 1.1429) - P(z < -1.1429)
= 0.8735 - 0.1265
= 0.747
Probability = 0.747
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