A new car that is a gas- and electric-powered hybrid has recently hit the market. The distance travelled on 1 gallon of fuel is normally distributed with a mean of 60 miles and a standard deviation of 7 miles. Find the probability of the following events:
A. The car travels more than 65 miles per gallon. Probability =
B. The car travels less than 54 miles per gallon. Probability =
C. The car travels between 52 and 67 miles per gallon. Probability =
Solution :
Given that ,
mean = = 60
standard deviation = = 7
A)
P(x >65) = 1 - P(x < 65)
= 1 - P((x - ) / < (65 - 60) / 7)
= 1 - P(z < 0.71)
= 1 - 0.7611 Using standard normal table.
= 0.2389
Probability = 0.2389
B)
P(x < 54) = P((x - ) / < (54 - 60) / 7)
= P(z < -0.86)
= 0.1949 Using standard normal table,
Probability = 0.1949
C)
P(52 < x < 67) = P((52 - 60)/ 7) < (x - ) / < (67 - 60) / 7) )
= P(-1.14< z < 1)
= P(z < 1) - P(z < -1.14)
= 0.8413 - 0.1271
= 0.7142
Probability = 0.7142
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