The following is an incomplete simple frequency distribution table for the number of mistakes made during a series of military combat readiness training exercises. Number of Mistakes Frequency 10–A 1 B–9 3 0–4 C N = 16 Find the missing values for A, B, and C. A = B = C =
the given data :-
number of mistakes | frequency |
10 - A | 1 |
B - 9 | 3 |
0 - 4 | C |
N = 16 |
the missing values be :-
A = 14 [ class width = 4 , the lower class limit = 10 , so, the upper class limit be = (10+4) = 14 ]
B = 5 [ as this is a discrete data...the upper class limit of previous class is 4, so, the lower class limit of next class be 5]
C = 12 [ total frequency = 16 , C = 16-(1+3) = 12 ]
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