x | P(X=x) | |||||
0 | 0.44 | |||||
The incomplete table at right is a discrete random variable x's probability distribution, where x is the number of days in a week people exercise. Answer the following: | 1 | 0.18 | ||||
2 | 0.02 | |||||
3 | ||||||
(a) | Determine the value that is missing in the table. | 4 | 0.03 | |||
5 | 0.13 | |||||
6 | 0.07 | |||||
(b) | Explain the meaning of " P(x < 2) " as it applies to the context of this problem. | 7 | 0.04 | |||
(c) | Determine the value of P(x > 4): | |||||
(d) | Find the probability that x is at least 1. | |||||
(e) | Find the mean (expected value) and standard deviation of this probability distribution. | |||||
(a) Here sum of all the probabilites shall be equal to 1.
= 1
0.44 + 0.18 + 0.02 + P(3) + 0.03 + 0.13 + 0.07 + 0.04 = 1
P(3) = 1 - 0.91 = 0.09
(b) Here the meaning of P(x < 2) is values of x that is less than 2. here it means the probability that number of days people exercise less than 2 in a week.
(c) P(x < 4) = P(0) + P(1) + P(2) + P(3) = 0.44 + 0.18 + 0.02 + 0.09 = 0.73
(d) P(x at least 1) = 1 - P(x is less than 1) =1 - P(0) = 1 - 0.44 = 0.56
(e) Mean = = 0 * 0.44 + 1 * 0.18 + 2 * 0.02 + 3 * 0.09 + 4 * 0.03 + 5 * 0.13 + 6 * 0.07 + 7 * 0.04 = 1.96
Standard deviation = Sqrt (Variance)
Variance = - ()2
= 0 * 0.44 + 1 * 1 * 0.18 + 2 * 2 * 0.02 + 3 * 3 * 0.09 + 4 * 4 * 0.03 + 5 * 5 * 0.13 + 6 * 6 * 0.07 + 7 * 7 * 0.04 = 9.28
Variance = 9.28 - 1.96 * 1.96 = 5.4384
Standard deviation = sqrt(5.4384) = 2.332
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