Question

Based on interviews with

8484

SARS patients, researchers found that the mean incubation period was

55

days, with a standard deviation of

15.415.4

days. Based on this information, construct a 95% confidence interval for the mean incubation period of the SARS virus. Interpret the interval.

The lower bound is

nothing

days. (Round to two decimal places as needed.) The upper bound is

nothing

days. (Round to two decimal places as needed.)

Interpret the interval. Choose the correct answer below.

A.

There is a 95% probability that the mean incubation period lies between the lower and upper bounds of the interval.

B.

There is 95% confidence that the mean incubation period is less than the lower bound of the interval.

C.

There is 95% confidence that the mean incubation period lies between the lower and upper bounds of the interval.

D.

There is 95% confidence that the mean incubation period is greater than the upper bound of the interval.

Answer #1

t critical value at 0.05 level with 83 df = 1.989

95% confidence interval for is

- t * S / sqrt(n) < < + t * S / sqrt(n)

55 - 1.989 * 15.4 / sqrt(84) < < 55 + 1.989 * 15.4 / sqrt(84)

51.66 < < 58.34

Lower bound = **51.66**

Upper bound = **58.34**

Interpretation -

**There is 95% confidence that the mean incubation period
lies between the lower and upper bounds of the
interval**

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