Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and the time a patrol car radios that it has arrived at the scene. Over a long period of time, it has been determined that the police response time has a normal distribution with a mean of 6.4 minutes and a standard deviation of 1.7 minutes. For a randomly received emergency call, find the following probabilities. (For each answer, enter a number. Round your answers to four decimal places.)
(a)
the response time is between 3 and 8 minutes
(b)
the response time is less than 3 minutes
(c)
the response time is more than 8 minutes
Solution :
Given that ,
mean = = 6.4 minutes
standard deviation = = 1.7 minutes
a) P( 3 < x < 8) = P[(3 - 6.4)/ 1.7) < (x - ) / < (8 - 6.4) / 1.7) ]
= P( -2.00 < z < 0.94)
= P(z < 0.94) - P(z < -2.00)
Using z table,
= 0.8264 - 0.0228
= 0.8036
b) P(x < 3) = P[(x - ) / < (3 - 6.4) / 1.7 ]
= P(z < -2.00)
Using z table,
= 0.0228
c) P(x > 8) = 1 - P(x < 8)
= 1 - P((x - ) / < (8 - 6.4) / 1.7)
= 1 - P(z < 0.94)
= 1 - 0.8264
= 0.1736
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